.TH std::chrono::year::year 3 "2024.06.10" "http://cppreference.com" "C++ Standard Libary"
.SH NAME
std::chrono::year::year \- std::chrono::year::year

.SH Synopsis
   year() = default;                          \fB(1)\fP \fI(since C++20)\fP
   constexpr explicit year( int y ) noexcept; \fB(2)\fP \fI(since C++20)\fP

   Constructs a year object.

   1) Default constructor leaves the year value uninitialized.
   2) If y is in the range [-32767, 32767], constructs a year object holding the year
   value y. Otherwise the value held is unspecified.

.SH Example


// Run this code

 #include <chrono>
 #include <iostream>

 int main()
 {
     using namespace std::chrono;

     constexpr int leap_years = []
     {
         int count{};
         for (int i{year::min()}; i <= int{year::max()}; ++i)
             if (year{i}.is_leap()) // uses constructor (2)
                 ++count;
         return count;
     } ();

     static_assert(15891 == leap_years);

     std::cout << "There are " << leap_years << " leap years in the range ["
               << int(year::min()) << ", " << int(year::max()) << "].\\n";
 }

.SH Output:

 There are 15891 leap years in the range [-32767, 32767].
